[填空题]
A force of 10.0 ± 0.2 N is appunxj:8 btt .0huxzx7)ybg 7 j/lie4 6)v cwg az8f8lg:. zej x,zmjw4u8tod to a mass of 2.0 ± 0.01 kg, causing it to accelerate. What mwov8fjt8 xzjge4cz .84 6,lu gw az:)is the percentage uncertainty of its acceleration? % (do not include the percent sign in your result)
参考答案: 2.50
本题详细解析: The acceleration is calculated using the formuy y,;w)wq4j e qat:v/wq6rs5mla: $$ a=\frac{F}{m} $$ so the percentage uncertainty on the acceleration is the sum of the percentage error on the force and on the mass. The percentage uncertainty on the force is: $$ \frac{0.2}{10.0} \times 100 \%=2 \% $$ The percentage uncertainty on the mass is:
$$ \frac{0.1}{2.0} \times 100 \%=5 \% . $$ Hence the percentage error on the acceleration will be $7 \%$.