[填空题]
The potential differenc4ub5)i zwvs jpbxx;-z6yw5/ xe gafnf na9284; x fvkbmoco28s,rilg 9( a9 9iu($V$) across a resistor is measured with a digital voltmeter to be $0.10 \; V$ . What is the percentage uncertainty in $V^2$ ? % (please only input numerical value without units and without the $\pm$ symbol.)
参考答案: 20.00
本题详细解析: The voltmeter is a digital device and so the uncertainty is the 82/biac qaur7 smallest value which it can record,uqa/728c iarb $0.01 \mathrm{~V}$. This is a $10 \%$ uncertainty on the $0.10 \mathrm{~V}$ measurement. The uncertainty in $V^2$ will be twice this, giving $20 \%$.